Hello, i have to find the following here:
- Inverse of the Line
- Function of the Line
the blue line is my attempt of the inverse
The inverse of a straight line will be a circle through the origin. It also has to pass through –1 (since that is its own inverse) and –j (which is the inverse of j. So the centre of the circle will be at $\displaystyle -\tfrac12-\tfrac12j$ and the radius will be $\displaystyle 1/\sqrt2$.