maximal domain of 1/(16-x^2) how do i figure it out?? thanks
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Originally Posted by tim_mannire maximal domain of 1/(16-x^2) how do i figure it out?? thanks $\displaystyle 16-x^2 \ne 0$ domain is $\displaystyle x \in \mathbb{R}$ , $\displaystyle x \ne \pm 4$ I'm not familiar with "maximal" domain.
Originally Posted by skeeter $\displaystyle 16-x^2 \ne 0$ domain is $\displaystyle x \in \mathbb{R}$ , $\displaystyle x \ne \pm 4$ I'm not familiar with "maximal" domain. I would assume it means "largest possible domain" which is exactly what you gave.
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