Question: Find an equation of the hyperbola with its center at the origin

Vertices: (+/- 3, 0);

Foci: (+/- 5, 0)

My work:

a = 3, c = 5

b^2 = c^2 - a^2

25 - 9 = 16

(y^2 / 25) - (x^2 / 16) = 1

I don't think this is right. Any corrections?

Results 1 to 7 of 7

- March 24th 2010, 10:48 AM #1

- Joined
- Nov 2009
- Posts
- 87

- March 24th 2010, 11:04 AM #2

- March 24th 2010, 11:44 AM #3

- Joined
- Nov 2009
- Posts
- 87

- March 24th 2010, 11:49 AM #4

- March 24th 2010, 11:50 AM #5

- Joined
- Nov 2009
- Posts
- 87

- March 24th 2010, 12:03 PM #6

- March 25th 2010, 03:16 AM #7

- Joined
- Apr 2005
- Posts
- 16,004
- Thanks
- 1657