Question: Find an equation of the hyperbola with its center at the origin

Vertices: (+/- 3, 0);

Foci: (+/- 5, 0)

My work:

a = 3, c = 5

b^2 = c^2 - a^2

25 - 9 = 16

(y^2 / 25) - (x^2 / 16) = 1

I don't think this is right. Any corrections?

Printable View

- Mar 24th 2010, 11:48 AMiluvmathbutitshardAm I right?
Question: Find an equation of the hyperbola with its center at the origin

Vertices: (+/- 3, 0);

Foci: (+/- 5, 0)

My work:

a = 3, c = 5

b^2 = c^2 - a^2

25 - 9 = 16

(y^2 / 25) - (x^2 / 16) = 1

I don't think this is right. Any corrections? - Mar 24th 2010, 12:04 PMharish21
- Mar 24th 2010, 12:44 PMiluvmathbutitshard
So

x^2 / 15 - y^2 / 16 = 1?

Thanks for answering - Mar 24th 2010, 12:49 PMharish21
- Mar 24th 2010, 12:50 PMiluvmathbutitshard
woops, sorry. Made a mistake :)

x^2 / 9 - y^2 / 16 = 1

Right?

Thank you! - Mar 24th 2010, 01:03 PMharish21
- Mar 25th 2010, 04:16 AMHallsofIvy