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Math Help - [SOLVED] Bouncing off an elliptical pool table and through a focal point

  1. #1
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    [SOLVED] Bouncing off an elliptical pool table and through a focal point

    http://img42.imageshack.us/img42/171/helphn.png

    I seriously in need of help. I found F1 already but i do know how to find X. I know you have to use the Line formula ( Y= Mx + B) but i cant seem to be able to get the answer.

    I found the slope for F1 and P, which is .15/.5 = 3/10. Afterward, I plugged into the line formula(y=Mx+b) which is Y= 3/10x+B. I get that you have to plug (-4,0) into B but i do not know how to do it. Any help/ suggestion? This question will be on the future FINAL. Thanks
    Last edited by namezox; March 23rd 2010 at 09:20 PM. Reason: Changed post title
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  2. #2
    Senior Member Stroodle's Avatar
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    *Edit Just reread your question...

    You can just use the formula y-y_1=m(x-x_1) to get the equation of the line that passes through F1 and P; where m is the gradient \frac{3}{10}, y_1 is the y-coordinate of the point (-4,0) and x_1 is the x-coordinate of the same point.
    Last edited by Stroodle; March 23rd 2010 at 11:12 PM.
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  3. #3
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    I solved it already tho. Thank you for the help. It was easy, just that I over-think the problem
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