# [SOLVED] Bouncing off an elliptical pool table and through a focal point

Printable View

• Mar 23rd 2010, 05:47 PM
namezox
[SOLVED] Bouncing off an elliptical pool table and through a focal point
http://img42.imageshack.us/img42/171/helphn.png

I seriously in need of help. I found F1 already but i do know how to find X. I know you have to use the Line formula ( Y= Mx + B) but i cant seem to be able to get the answer.

I found the slope for F1 and P, which is .15/.5 = 3/10. Afterward, I plugged into the line formula(y=Mx+b) which is Y= 3/10x+B. I get that you have to plug (-4,0) into B but i do not know how to do it. Any help/ suggestion? This question will be on the future FINAL. Thanks
• Mar 23rd 2010, 09:58 PM
Stroodle
*Edit Just reread your question...

You can just use the formula $\displaystyle y-y_1=m(x-x_1)$ to get the equation of the line that passes through $\displaystyle F1$ and $\displaystyle P$; where $\displaystyle m$ is the gradient $\displaystyle \frac{3}{10}$, $\displaystyle y_1$ is the y-coordinate of the point $\displaystyle (-4,0)$ and $\displaystyle x_1$ is the x-coordinate of the same point.
• Mar 23rd 2010, 11:01 PM
namezox
I solved it already tho. Thank you for the help. It was easy, just that I over-think the problem