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$\displaystyle \frac{9x^2+x-1}{x^2*(x+1)}$

Quote: Originally Posted by Selim $\displaystyle \frac{9x^2+x-1}{x^2*(x+1)}$ You would need to set it up as $\displaystyle \frac{A}{x} + \frac{Bx + C}{x^2} + \frac{D}{x + 1} = \frac{9x^2 + x - 1}{x^2(x + 1)}$.