# location of asymptotes and points of discontinuity

• Apr 10th 2007, 04:56 AM
power2600
location of asymptotes and points of discontinuity
2x+5
_______
(x-1)(x+5)

Determine the location of asymptotes and points of discontinuity if they exist.

I know how to solve it with graphing but how do I find it without graphing?
• Apr 10th 2007, 05:42 AM
earboth
Quote:

Originally Posted by power2600
2x+5
_______
(x-1)(x+5)

Determine the location of asymptotes and points of discontinuity if they exist.
I know how to solve it with graphing but how do I find it without graphing?

Hello,

I assume that you should examine the function:
Code:

```        2x+5 f(x) = ----------       (x-1)(x+5)```
1. Calculate the domain of f: d = IR \ {-5, 1} because the denominator must be unequal to zero. The equations x = -5 and x = 1 describe the vertical asymptotes

2.
Code:

```        2x+5 f(x) = -----------       x² + 4x - 5```
The degree ofthe numerator is smaller than the degree of the denominator therefore f has a horizontal asymptote: y = 0 (or in other words: The x-axis is a sysmptote of f)

I've attached a diagram of the function.