how do i factor this completely to find the zeros and then state the multiplcity of each zero??
p(x)= x^3-x^2+x
To factor this completely first look for a common factor
$\displaystyle p(x)= x^3-x^2+x$
$\displaystyle x$ is common to all terms, taking that out gives.
$\displaystyle p(x)= x(x^2-x+1)$
The remaining expression cannot be factored $\displaystyle \in \mathbb{R}$