Math Help - What do I do next?

1. What do I do next?

Question: Find Pk+1 for the given Pk.
Pk = k/2 (3k-1)

So basically for every k, I put k+1.
Therefore:

(k+1)/(2) [3(k+1)-1]
This may sound stupid, but how do I simplify from here?

Any help is appreciated.

2. Originally Posted by iluvmathbutitshard
Question: Find Pk+1 for the given Pk.
Pk = k/2 (3k-1)

So basically for every k, I put k+1.
Therefore:

(k+1)/(2) [3(k+1)-1]
This may sound stupid, but how do I simplify from here?

Any help is appreciated.
$\frac{k+1}{2} \left[3(k+1) - 1\right]
$

$\frac{k+1}{2} \left(3k+3-1\right)$

$\frac{k+1}{2} \left(3k+2\right)$

$\frac{(k+1)(3k+2)}{2}
$