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Math Help - What do I do next?

  1. #1
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    What do I do next?

    Question: Find Pk+1 for the given Pk.
    Pk = k/2 (3k-1)

    So basically for every k, I put k+1.
    Therefore:

    (k+1)/(2) [3(k+1)-1]
    This may sound stupid, but how do I simplify from here?

    Any help is appreciated.
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  2. #2
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    Quote Originally Posted by iluvmathbutitshard View Post
    Question: Find Pk+1 for the given Pk.
    Pk = k/2 (3k-1)

    So basically for every k, I put k+1.
    Therefore:

    (k+1)/(2) [3(k+1)-1]
    This may sound stupid, but how do I simplify from here?

    Any help is appreciated.
    \frac{k+1}{2} \left[3(k+1) - 1\right]<br />

    \frac{k+1}{2} \left(3k+3-1\right)

    \frac{k+1}{2} \left(3k+2\right)

    \frac{(k+1)(3k+2)}{2}<br />
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