Question: Find Pk+1 for the given Pk.

Pk = k/2 (3k-1)

So basically for every k, I put k+1.

Therefore:

(k+1)/(2) [3(k+1)-1]

This may sound stupid, but how do I simplify from here?

Any help is appreciated.

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- Mar 18th 2010, 02:21 PMiluvmathbutitshardWhat do I do next?
Question: Find Pk+1 for the given Pk.

Pk = k/2 (3k-1)

So basically for every k, I put k+1.

Therefore:

(k+1)/(2) [3(k+1)-1]

This may sound stupid, but how do I simplify from here?

Any help is appreciated. - Mar 18th 2010, 02:29 PMskeeter