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  1. #1
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    easy question

    Simplify $\displaystyle (2p^{-2}q)^3$X $\displaystyle \frac{1}{2}p^2q^-1$
    Last edited by mastermin346; Mar 18th 2010 at 10:26 AM.
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  2. #2
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    Quote Originally Posted by mastermin346 View Post
    Simplify $\displaystyle (2p^{-2}q)^3\left(\frac{1}{2}p^2q^{-1}\right)$
    ... I assume the above Latex correction is what you meant?
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  3. #3
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    Quote Originally Posted by mastermin346 View Post
    Simplify $\displaystyle (2p^{-2}q)^3$X $\displaystyle \frac{1}{2}p^2q^{-1}$
    First use "$\displaystyle (a^nb^m)^p= a^{np}b^{mp}$" and then "$\displaystyle a^ia^j= a^{i+j}$".
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