Find $\displaystyle \frac{dy}{dx} $ for the following, leaving your answer in terms of the parameter t.

$\displaystyle x = 2t-sin2t $

$\displaystyle y = 1-cos2t $

$\displaystyle \frac{dx}{dt} = 2-2cos2t $

$\displaystyle \frac{dy}{dt} = 2sin2t $

$\displaystyle \frac{dy}{dx} = \frac{2sin2t}{2-2cos2t} $

I can factor and cancel the two's but that still does give me the correct answer. Can someone please show me what I am doing wrong?

Thank you.