I need to calculate the sum of the first n terms of ln(a)^n÷n! where 0≤n≥10. What values of a can I use? EDIT: sorry i meant 0≤n≤10
Last edited by Shadow2793; Mar 14th 2010 at 05:50 PM.
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Originally Posted by Shadow2793 where 0≤n≥10 ??????? I think you meant $\displaystyle 0\leq n \leq 10$ you can use all values of $\displaystyle a$ that don't cause problems with the range of $\displaystyle \ln(a), i.e., a > 0.$
Are you sure there is a stipulation on the value of $\displaystyle n?$ If this is in fact an infinite series then we have: $\displaystyle \sum_{n=0}^{\infty} \frac{\ln(a)^n}{n!} = e^{ln(a)} = a$ where $\displaystyle a>0.$
ok, thank you all
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