Stuck on two questions that was in a review section.
1) How can I graph the ellipse: x^2/4 + y^2/36 = 1?
2) How do I solve for x: 3x/2 - 3/4 = x/8?
Here's what I've done so far:
3x(4)/2 - 3(2)/4 = x/8
12x/2 - 6/4 = x/8
48x/8 - 12/8 = 4x/32.........this is where I got stuck when trying to get all the denominators the same.
Thanks in advance.
Hello, Mulya66!
Graph the ellipse: .x²/4 + y²/36 .= .1
First of all, the ellipse is centered at the origin.
Recall that the denominators give you the "dimensions" of the ellipse.
Since a² = 4, a = ±2.
. . The ellipse extends 2 units to the left and right of center.
Since b² = 36, b = ±6.
. . The ellipse extends 6 units up and down from the center.
2) Solve: .3x/2 - 3/4 .= .8/x
Multiply through by the LCM, 4x
. . . . 3x . - . .3 . . . . . 8
. . 4x·--- - 4x·-- .= .4x·-- . → . 6x² - 3x .= .32
. . . . .2 . - . .4 . - . - . x
and solve the quadratic equation.