What angle? You say in the problem that the ball is thrown at an angle of 25 degrees so presumably that is not the angle you are talking about. Go back and read the problem carefully.I Set the equation 215 = (75 cos X)t but there are two variables so I don't know how to solve it.
Pretty much what you have with 3500 feet added to the vertical. The initial motion of the supplies is the same as the initial motion of the airplane so it is 300 mph horizontally, 0 vertically.If an airplane flying at an altitiude of 3500 feet is dropping supplies, the path of the plane is parallel to the ground as the supplies are released while it travels 300mph, what are the parametric equations that represents this?
x= (300 mph) t,
You will need to think about your units of measurement. If t is in seconds or minutes and you are measuring distance in feet, you will have to convert "300 mph" to "feet per minute" or "feet per second" before doing any calculation.