ln(x)+3ln(2)+1=0
HELLO
First, isolate for the term in $\displaystyle x$ :
$\displaystyle \ln{(x)} + 3 \ln{(2)} + 1 = 0$
$\displaystyle \ln{(x)} = - 3 \ln{(2)} - 1$
Now exponentiate with base $\displaystyle e$ :
$\displaystyle x = e^{- 3 \ln{(2)} - 1}$
This is approximatively equal to :
$\displaystyle x \approx 0.046$
And can be written as a fraction as follows :
$\displaystyle x = \frac{1}{8e}$
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