Thread: [SOLVED] Logistic Growth (quick)

Hey guys, need some help with this.

So, first I'm assuming I have to solve for A so:

505 = A / 1+10^k(2000-2000)

505 = A/2

1010 = A, then I substitute 1010 in for A getting:

N(t) = 1010 / 1+(10^(-1(2002-2000)))

N(t) = 1010 / 1.01

= 1000?? Can anyone verify this for me please?

Yes, 1000 is correct. Good job!

Thanks Ivy!