Hi, This has complex numbers in I have the equation where the solutions for z= -2-i, -2+i and 2. How do I go about finding a, b and c? I've tried subbing back into the equation but it ends up getting far too complicated

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(z-2)(z+2-i)(z+2+i)=0 (z-2)((z+2)^2-i^2)=0 z^3+2z^2-3z-10=0