1. Analytic Trigonometry

Help me, im trying everything and its not working

Verify that the x-values are solutions of the equation.

$\displaystyle 3tan^2(2x-1) = 0$
$\displaystyle a.) x = \pi/12$
$\displaystyle b.) x = 5\pi/12$

i need to know the steps. thanks a bunch!

2. Originally Posted by hydride
Help me, im trying everything and its not working

Verify that the x-values are solutions of the equation.

$\displaystyle 3tan^2(2x-1) = 0$
$\displaystyle a.) x = \pi/12$
$\displaystyle b.) x = 5\pi/12$

i need to know the steps. thanks a bunch!
apparently these are not the solutions

3. Originally Posted by hydride
Help me, im trying everything and its not working

Verify that the x-values are solutions of the equation.

$\displaystyle 3tan^2(2x-1) = 0$
$\displaystyle a.) x = \pi/12$
$\displaystyle b.) x = 5\pi/12$

i need to know the steps. thanks a bunch!
Dear hydride,

$\displaystyle x=\frac{\pi}{12}~and~x=\frac{5\pi}{12}$ are not solutions of the given trignometric equation.

For example, $\displaystyle 3tan^{2}(2x-1)=2.07\times{10^{-4}}~when~x=\frac{\pi}{12}$