# Analytic Trigonometry

• Mar 1st 2010, 04:00 PM
hydride
Analytic Trigonometry
Help me, im trying everything and its not working(Doh)

Verify that the x-values are solutions of the equation.

$\displaystyle 3tan^2(2x-1) = 0$
$\displaystyle a.) x = \pi/12$
$\displaystyle b.) x = 5\pi/12$

i need to know the steps. thanks a bunch!
• Mar 1st 2010, 04:16 PM
bigwave
Quote:

Originally Posted by hydride
Help me, im trying everything and its not working(Doh)

Verify that the x-values are solutions of the equation.

$\displaystyle 3tan^2(2x-1) = 0$
$\displaystyle a.) x = \pi/12$
$\displaystyle b.) x = 5\pi/12$

i need to know the steps. thanks a bunch!

apparently these are not the solutions
• Mar 1st 2010, 04:17 PM
Sudharaka
Quote:

Originally Posted by hydride
Help me, im trying everything and its not working(Doh)

Verify that the x-values are solutions of the equation.

$\displaystyle 3tan^2(2x-1) = 0$
$\displaystyle a.) x = \pi/12$
$\displaystyle b.) x = 5\pi/12$

i need to know the steps. thanks a bunch!

Dear hydride,

$\displaystyle x=\frac{\pi}{12}~and~x=\frac{5\pi}{12}$ are not solutions of the given trignometric equation.

For example, $\displaystyle 3tan^{2}(2x-1)=2.07\times{10^{-4}}~when~x=\frac{\pi}{12}$