logarithm problem

Quote:

Originally Posted by mastermin346

how to solve this question

$<br /> <br /> 2+\log_2{(3x-1)}=\log_2{4x}<br />$

1. Re-write the equation:

$2+\log_2{(3x-1)}=\log_2{4x}~\implies~2=\log_2{4x} - \log_2{(3x-1)}~\implies~$ $2=\log_2\left( \frac{4x}{(3x-1)}\right)$

2. Now use the base 2 on both sides of the equation:

$4=\frac{4x}{(3x-1)}$ Solve for x. Keep in mind that $x > \tfrac13$ .