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Math Help - Rectangular coordinate

  1. #1
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    Rectangular coordinate

    How would I find the rectangular coordinate of the point P on the unit circle that corresponds to t=-[pi]/2?
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    Quote Originally Posted by gretchen View Post
    How would I find the rectangular coordinate of the point P on the unit circle that corresponds to t=-[pi]/2?
    Hello, Gretchen,

    the point P has the coordinates P(r*cos(t), r*sin(t)). Since r = 1 the point P is P(0, -1)

    EB
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    Quote Originally Posted by gretchen View Post
    How would I find the rectangular coordinate of the point P on the unit circle that corresponds to t=-[pi]/2?
    x = r*cos(theta)
    y = r*sin(theta)

    The point is (1, -(pi)/2), so we have:
    x = 1*cos(-(pi)/2) = 1*cos((pi)/2) = 1*0 = 0
    y = 1*sin(-(pi)/2) = -1*sin((pi)/2) = -1*1 = -1

    So the point (1, -(pi)/2) corresponds to the rectangular coordinate point (0, -1).

    -Dan
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