How would I find the rectangular coordinate of the point P on the unit circle that corresponds to t=-[pi]/2?
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Originally Posted by gretchen How would I find the rectangular coordinate of the point P on the unit circle that corresponds to t=-[pi]/2? Hello, Gretchen, the point P has the coordinates P(r*cos(t), r*sin(t)). Since r = 1 the point P is P(0, -1) EB
Originally Posted by gretchen How would I find the rectangular coordinate of the point P on the unit circle that corresponds to t=-[pi]/2? x = r*cos(theta) y = r*sin(theta) The point is (1, -(pi)/2), so we have: x = 1*cos(-(pi)/2) = 1*cos((pi)/2) = 1*0 = 0 y = 1*sin(-(pi)/2) = -1*sin((pi)/2) = -1*1 = -1 So the point (1, -(pi)/2) corresponds to the rectangular coordinate point (0, -1). -Dan
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