PLS HELP...Exponents and Logs

Quote:

Originally Posted by mathhtam

The Richter magnitude, R, of an earthquarge is given by,
R=0.67log(0.37E)+1.46
where E is the energy in kW X h released by the earthquake.

Show that E=2.7 X 10 ^(R-1.46)/0.67

You have:

$R=0.67 \log_{10}(0.37 E)+1.46$

so rearrange so that the $\log_{10}$ is on one side and everything else on the other:

$\log_{10} (0.37 E)=\frac{R-1.46}{0.67}$

By definition if $\log_{10}(a)=b$ then $a=10^b$ , so:

$<br /> 0.37 E=10^{\frac{R-1.46}{0.67}}<br />$

and you should be able to finish it yourself from there.

CB