To solve the integral, raise x to the second power and divide it by 2, and add an x to pi to get:
(2x)/2 + pi(x) + C
Now just solve the integral for pi to -pi, so you would just sub in and solve by subtracting the second number solved in the indefinite integral, minus the first.
((2pi)/2 + pi(pi)) - ((2(-pi)/2 + pi(-pi))
(4pi)/2 + 2(pi)^2
You just said "raise x to the second power" but now you write "2x"!
That should be
And apparently that was not just a typo since you now calculate 2 times pi rather than squareing. You should haveNow just solve the integral for pi to -pi, so you would just sub in and solve by subtracting the second number solved in the indefinite integral, minus the first.
((2pi)/2 + pi(pi)) - ((2(-pi)/2 + pi(-pi))
(4pi)/2 + 2(pi)^2