Solution to the exponential equation:

3^2x-1=5

Solve the logarithmic equation for X:

ln(2 + X) =1

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- Feb 25th 2010, 04:38 AMaligator0207Exponential Equations.
Solution to the exponential equation:

3^2x-1=5

Solve the logarithmic equation for X:

*ln*(2 + X) =1 - Feb 25th 2010, 04:46 AMmathaddict
- Feb 25th 2010, 07:39 AMaligator0207
What happened to the (-1) in problem 1? And at the end, do I put that into my calculator?

- Feb 25th 2010, 08:02 AMGrandad
Hello aligator0207I suspect that you should have put brackets around the 2x-1 and that the original equation was actually:

$\displaystyle 3^{2x-1}=5$and, if so, the working should be:$\displaystyle (2x-1)\log3=\log5$Grandad

$\displaystyle \Rightarrow 2x-1 = \frac{\log5}{\log3}$

$\displaystyle \Rightarrow x = \frac12\left(1+\frac{\log5}{\log3}\right)$$\displaystyle =\frac{\log3+\log5}{2\log3}$

$\displaystyle =\frac{\log15}{\log9}$

$\displaystyle =1.2325$