Hey. I have a question here I was hoping to get a hand with.

Determine the slope of the tangent at x = 3 for the function :

f(x) = (4x^3) / sinx

Note -- x is measured in radians

I've gotten the derivative without a problem, it looks like this:

(12x^2)(1/sinx) - (4x^3) (1/(sinx^2))(cosx)

I think where I'm getting hung up is the radians issue. I know the pi rad = 180 deg... but could you help me figure this out. My book is giving (sinx) as equal to 0.1411. Thanks.