use the binomial theorem to expand up to 4 terms

$1/sqrt(4-3x^2)^3$

2. Originally Posted by joey1
use the binomial theorem to expand up to 4 terms

$1/sqrt(4-3x^2)^3$
$\frac{1}{\sqrt{(4 - 3x^2)^3}} = (4 - 3x^2)^{-\frac{3}{2}}$.

Now recall that

$(x + y)^r = x^r + rx^{r - 1}y + \frac{r(r - 1)}{2!}x^{r - 2}y^2 + \frac{r(r - 1)(r - 2)}{3!}x^{r - 3}y^3 + \dots$

Substitute the values of $x, y, r$ and simplify...