x^4-3=2x+1 how can i solve it ? thanks in advance
Follow Math Help Forum on Facebook and Google+
Originally Posted by alessandromangione x^4-3=2x+1 how can i solve it ? thanks in advance I don't think you'll have much luck algebraically as both of the real roots appear to be transcendental.
then i use the formula b^2 -square root of 4ac / 2a and i get x=0 and x=4...is it correct?
Originally Posted by alessandromangione then i use the formula b^2 -square root of 4ac / 2a and i get x=0 and x=4...is it correct? That formula only works on quadratic equations and the equation in the original post is a quartic (x^4) Did you mean or Given then the quadratic formula is
Originally Posted by e^(i*pi) That formula only works on quadratic equations and the equation in the original post is a quartic (x^4) Did you mean or Given then the quadratic formula is i mean x^4...so what formula can i use instead?
Originally Posted by alessandromangione i mean x^4...so what formula can i use instead? You can't, at least not to my knowledge. You'd have to use technology to get an iterative solution Wolfram guesses too: http://www.wolframalpha.com/input/?i=x^4-3%3D2x%2B1+
View Tag Cloud