# Math Help - Please help with inequalities

1. ## Please help with inequalities

$
\frac{5x^2 - 20x - 36}{x-5}
\leq 4x
$

2. Originally Posted by BadMaterial
$
\frac{5x^2 - 20x - 36}{x-5}
\leq 4x
$
$\frac{5x^2 - 20x - 36}{x-5}\leq 4x$
$\frac{5x^2 - 20x - 36}{x-5}- 4x\leq 0$
$\frac{x^2 - 36}{x-5}\leq 0$

Now solve it.