seeing that r^2(1+m^2)=b^2...use this method to find an equation of the tangent line to the circle x^2+y^2=9 at the point ( 1, 2square root of 2 )

i'm totally lost...thanks in advance

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- Feb 18th 2010, 05:41 PMalessandromangionefinding the equation of the tangent line to a circle
seeing that r^2(1+m^2)=b^2...use this method to find an equation of the tangent line to the circle x^2+y^2=9 at the point ( 1, 2square root of 2 )

i'm totally lost...thanks in advance - Feb 18th 2010, 06:36 PMskeeter
- Feb 18th 2010, 09:50 PMalessandromangione
- Apr 12th 2010, 10:26 PMlsp2010I need help! ):
I am completely stuck on this problem. please help me work it out. ):

Find a formula that gives the slope of a line tangent to the circle (x^2)+(y^2)=(r^2) at any point (in the first quadrant) (x,sqrt((r^2)-y^2)). - Apr 12th 2010, 11:13 PMsa-ri-ga-ma
- Apr 13th 2010, 11:20 AMearboth
1. If your equation is satisfied by r, m and b the line in question is a tangent (in Germany this equation is called "condition for the existance of a tangent to a circle")

2. The tangent point is

3. Consequently you'll get a system of equations:

4. Solve this system for b and m and plug in these values into the equation of a straight line.

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