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Math Help - find the general form of the equation of each circle

  1. #1
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    find the general form of the equation of each circle

    with the endpoints of a diameter at (1,4) (-3,2)

    so for the radius i have to find the distance between these two points...and i got square root of 20...then..?

    hope u guys can help me

    thanks
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  2. #2
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    Quote Originally Posted by alessandromangione View Post
    with the endpoints of a diameter at (1,4) (-3,2)

    so for the radius i have to find the distance between these two points...and i got square root of 20...then..?

    hope u guys can help me

    thanks
    \sqrt{20} is the diameter, not the radius.

    the midpoint between the two points is the circle's center, (h,k)

    (x-h)^2 + (y-k)^2 = r^2
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  3. #3
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    Quote Originally Posted by skeeter View Post
    \sqrt{20} is the diameter, not the radius.

    the midpoint between the two points is the circle's center, (h,k)

    (x-h)^2 + (y-k)^2 = r^2
    so the the radiuus is square root of 10?
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  4. #4
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    Quote Originally Posted by alessandromangione View Post
    so the the radiuus is square root of 10?
    I have to believe that you were taught better than that ...

    \frac{\sqrt{20}}{2} \ne \sqrt{10}


    \frac{\sqrt{20}}{2} = \frac{\sqrt{20}}{\sqrt{4}} = \sqrt{\frac{20}{4}} = \sqrt{5}<br />
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