with the endpoints of a diameter at (1,4) (-3,2) so for the radius i have to find the distance between these two points...and i got square root of 20...then..? hope u guys can help me thanks
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Originally Posted by alessandromangione with the endpoints of a diameter at (1,4) (-3,2) so for the radius i have to find the distance between these two points...and i got square root of 20...then..? hope u guys can help me thanks $\displaystyle \sqrt{20}$ is the diameter, not the radius. the midpoint between the two points is the circle's center, $\displaystyle (h,k)$ $\displaystyle (x-h)^2 + (y-k)^2 = r^2$
Originally Posted by skeeter $\displaystyle \sqrt{20}$ is the diameter, not the radius. the midpoint between the two points is the circle's center, $\displaystyle (h,k)$ $\displaystyle (x-h)^2 + (y-k)^2 = r^2$ so the the radiuus is square root of 10?
Originally Posted by alessandromangione so the the radiuus is square root of 10? I have to believe that you were taught better than that ... $\displaystyle \frac{\sqrt{20}}{2} \ne \sqrt{10}$ $\displaystyle \frac{\sqrt{20}}{2} = \frac{\sqrt{20}}{\sqrt{4}} = \sqrt{\frac{20}{4}} = \sqrt{5} $
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