If y = A*sin(Bx + C) + D is substituted as y = -1.5 sin(x + π/4) + 4, what

would the cosine function be in order to match the graph of said sine

function?

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- Feb 18th 2010, 07:13 AMzacharyrody = sine x = cos x
If y = A*sin(Bx + C) + D is substituted as y = -1.5 sin(x + π/4) + 4, what

would the cosine function be in order to match the graph of said sine

function? - Feb 18th 2010, 07:18 AMe^(i*pi)
Note that $\displaystyle \cos(x) = \sin \left(x - \frac{\pi}{2}\right)$. You can show this using the subtraction formula for sin. In terms of the graphs it means the graph of cos(x) is shifted by pi/2 to the right on the x axis

Only C would change as it's a phase difference

$\displaystyle -1.5\cos \left(x + \frac{\pi}{4} - \frac{\pi}{2}\right) + 4 = -1.5\cos \left(x - \frac{\pi}{4}\right) + 4$ - Feb 18th 2010, 07:44 AMChris11
-1.5cos(x-π/4)+4