dy/dx = im unsure about this can anyone help or correct me? many thanks
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First of all, is not correct, x cubed will be to the one half power, because you are taking the square root of it, not the cube root. To differentiate, you multiply ((x^3)^(1/2)) and x^(1) to get (x^3)^(3/2) + 1 Now, differentiate: dy/dx = (3/2)(x^3)^(1/2)*(3x^2)
You also appear not to have "distributed": Now, use that the derivative of is .
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