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Math Help - resolving for x

  1. #1
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    finding de value of x

    I tried to solve thees but is useless I not doing it right. Can some one lead the way?


    1) sqrt(2x + 1) = x-1


    2) -2< x+2/x-1
    Last edited by cristinaivelisse; February 17th 2010 at 04:35 PM.
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  2. #2
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    Quote Originally Posted by cristinaivelisse View Post
    I tried to solve thees but is useless I not doing it right. Can some one lead the way?


    1) sqrt(2x + 1) = x-1


    2) -2< x+2/x-1

    \sqrt{2x+1} = x-1

    square both sides ...

    2x+1 = x^2 - 2x + 1

    0 = x^2 - 4x

    0 = x(x-4)

    x = 0 , x = 4

    check for extraneous solution(s)



    -2 < \frac{x+2}{x-1}

    0 < 2 + \frac{x+2}{x-1}

    0 < \frac{2(x-1)}{x-1} + \frac{x+2}{x-1}

    0 < \frac{3x}{x-1}

    critical values are x = 0 and x = 1. these two values of x break up the set of all x-values into three sections . ..

    x < 0 , 0 < x < 1 , and x > 1

    pick any number in each section ... if it makes the original inequality true, then all values of x in that section will be in the solution set.
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