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Math Help - could some check solution please

  1. #1
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    could some check solution please

    Given the function

    y= \frac{x+1}{x}

    a. Find the equation of the tangent to the curve at the point (2,(3/2))

    b. Find the value of x where the tangent to the curve is
    perpendicular to the tangent found in part (a)

    <br />
\frac{x+1}{x}= \frac{1}{x} - \frac{x+1}{x^2}

    <br />
\frac{1}{2} - \frac{2+1}{2^2}

    m= 1/4

    y-y1=m(x-x1)
    y- (3/2) = 1/4(x-2)
    y= 1/4x +1


    part B

    M1,M2 = -1
    1/4 M2 = -1
    m2 = 4

    y- (3/2) = 4(x-2)
    y=4x-6.5

    if some could confirm iif ihave done things correct mucho gratis
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  2. #2
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    G'day, I think your on the right track,

    I would say y= \frac{x+1}{x} =  1+\frac{1}{x} then y' = \frac{-1}{x^2}

    Then find y'(2) = \frac{-1}{2^2}=\frac{-1}{4} to make m in the tangent equation.
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  3. #3
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    yeah, it looks good
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