could some check solution please

Given the function

$\displaystyle y= \frac{x+1}{x}$

a. Find the equation of the tangent to the curve at the point (2,(3/2))

b. Find the value of x where the tangent to the curve is

perpendicular to the tangent found in part (a)

$\displaystyle

\frac{x+1}{x}= \frac{1}{x} - \frac{x+1}{x^2}$

$\displaystyle

\frac{1}{2} - \frac{2+1}{2^2}$

m= 1/4

y-y1=m(x-x1)

y- (3/2) = 1/4(x-2)

**y= 1/4x +1**

part B

M1,M2 = -1

1/4 M2 = -1

m2 = 4

y- (3/2) = 4(x-2)

**y=4x-6.5**

if some could confirm iif ihave done things correct mucho gratis(Cool)