The tangent to the curve at the point A where , meets the y-axis at B(0,8). Find the gradient of the curve at point A. I have attempted using differentiation and found the gradient to be 12p... However, gradient must be in value form..
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Originally Posted by Punch The tangent to the curve at the point A where , meets the y-axis at B(0,8). Find the gradient of the curve at point A. I have attempted using differentiation and found the gradient to be 12p... However, gradient must be in value form.. hi At x=2 , y=p(2)^3=8p so the tangent touches the curve at (2,8p) gradient of tangent = (8p-8)/2 so 8p-8/2=12p ..
I already did this in my attempt... The gradient MUST be in value form.
Originally Posted by Punch I already did this in my attempt... The gradient MUST be in value form. look closer , , solving this , p=-1/2 so dy/dx=12p=12(-1/2)=-6
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