complete the square ...
the parabola's vertex is located at , therefore the range is
The problem is h(x) = x^2 + 8x
I know the domain is all real. But did I solve for x correctly?
I have set up the problem:
y = x^2 + 8x
y = x(x + 8)
y/x = x + 8
y/x - 8 = x
y-8 = x^2
x = square root y - 8
But I don't get how they got the answer of x is greater than or equal to -16. Please help me.