If f(x) = $\displaystyle e^xg$(x), where g(0) = 2 and g'(0) = 5, find f '(0).
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Originally Posted by ryan18 If f(x) = $\displaystyle e^xg$(x), where g(0) = 2 and g'(0) = 5, find f '(0). Hi ryan18, $\displaystyle f(x)=e^xg(x)$ $\displaystyle f'(x)=g(x)\frac{d}{dx}e^x+e^x\frac{d}{dx}g(x)=g(x) e^x+e^xg'(x)$ $\displaystyle f'(0)=g(0)e^0+e^0g'(0)=g(0)+g'(0)$
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