find the square roots of 3-4j
i used a software prog for the method, just want to check if it right?
-4j+3=0
-4j=-3
j=3/4
manny thanks
Do you understand that 3 - 4j is a complex number and your job is to find two other complex numbers of the form $\displaystyle a + jb$ (where a and b are real) such that $\displaystyle (a + jb)^2 = 3 - 4j$?
Note for the uninitiated: j is the symbol for $\displaystyle \sqrt{-1}$ used by electrical engineers.