Hey folks. I have a question here... Determine the derivative of the following function: f(x) = sin(e^x) I know that f '(x) = cosx... but I'm having a hard time putting it together. Thanks!
Follow Math Help Forum on Facebook and Google+
Originally Posted by Jools Hey folks. I have a question here... Determine the derivative of the following function: f(x) = sin(e^x) I know that f '(x) = cosx... but I'm having a hard time putting it together. Thanks! Do you know the chain rule? $\displaystyle f(x) = f(g(x))$ $\displaystyle f'(x) = f'(g(x)).g'(x)$ $\displaystyle f(x) = sin(e^x)$ $\displaystyle f'(x) = cos(e^x).e^x$ This should make sense if you are familiar with the chain rule.
Use the chain rule and note that the derivative of e^x is e^x Spoiler: $\displaystyle e^x \, cos(e^x)$
Originally Posted by e^(i*pi) Use the chain rule and note that the derivative of e^x is e^x Spoiler: $\displaystyle e^x \, cos(e^x)$ Ok... Got it I think. Thanks.
View Tag Cloud