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Math Help - finding the equation of a straight line

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    finding the equation of a straight line

    i'm trying to find the equation of a straight line in y-mx+c from that is parallel to the line with the equation 3x+6y=8, passing through(2,2)
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    Quote Originally Posted by johnsy123 View Post
    i'm trying to find the equation of a straight line in y-mx+c from that is parallel to the line with the equation 3x+6y=8, passing through(2,2)
    Write the parallel line you are given in y = mx + c form.

    3x + 6y = 8

    6y = -3x + 8

    y = -\frac{1}{2}x + \frac{4}{3}.

    Parallel lines have the same gradient. The gradient of the parallel line is -\frac{1}{2}, so the line you are trying to find has gradient -\frac{1}{2}.


    The line you are trying to find has gradient m = -\frac{1}{2}, and you know the point (x, y) = (2, 2) lies on the line.

    So y = mx + c

    2 = -\frac{1}{2}(2) + c

    2 = -1 + c

    3 = c.


    So the equation of the line is y = -\frac{1}{2}x + 3.
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