i am having trouble with this sequence:
x1=3 xn+1=0.8 xn-5 (n=1,2,3....)
how do i find a closed form, also in the tenth term correct to 4SF
Can someone explain how can i describe a long term behaviour of the sequence
many thanks
rich
i am having trouble with this sequence:
x1=3 xn+1=0.8 xn-5 (n=1,2,3....)
how do i find a closed form, also in the tenth term correct to 4SF
Can someone explain how can i describe a long term behaviour of the sequence
many thanks
rich
I take it that you mean $\displaystyle x_1= 3$ and $\displaystyle x_{n+1}= 0.8x_n- 5$. Notice that $\displaystyle x_2= 0.8x_1- 5$ and then $\displaystyle x_3= 0.8(0.8x_1- 5)- 5= x_1(0.8)^2- 5(0.8)- 5$, $\displaystyle x_4= 0.8((0.8)^2x_1- 5(0.8)- 5)- 5= x_1(0.8)^3- 5(0.8)^2- 5(0.8)- 5$