having trouble with this one solve for x using logs 2e^3x=4e^5x thanks!
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First, I would divide by 2 to produce: Take the natural logarithm. Subtract 5x. Divide by -2.
Helolo, aldric! Another approach . . . Solve for using logs: . We have: . Divide by Take logs: . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .
i.e. . At least, It has nice from. =)
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