two questons, are they both quadratic? if anyone could get me started much appreciated.
(a) $\displaystyle 3{^2{^x}}+ 8 . 3{^x}-9=0$ (multiply 8 x 3x)
(b) $\displaystyle e{^2{^x}}+ 8e{^x}=3^2 $
b)
define $\displaystyle e^x = u$ then the equation is equivalent to $\displaystyle u^2+8u-9=0$
Factoring
$\displaystyle (u+9)(u-1)=0$
solutions $\displaystyle u=1$ and $\displaystyle u=-9$
As the exponential negative values does not yield, the solution is
$\displaystyle u=1=e^x \rightarrow x=0$