Calculate the gradient of the tangent to the curve at
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If your question is to calculate the derivative of the function here is step by step The derivate of is calculated using the chain rule can now conclude
Since you will need to use the chain rule on the square root anyway, you might find it easier to do this as and use the product rule rather than the quotient rule.
Thanks to both of you with your reply, I will try it out!!
Originally Posted by danielomalmsteen If your question is to calculate the derivative of the function here is step by step The derivate of is calculated using the chain rule can now conclude Hi, I am well aware of the formula to use, the problem lies in simplifying the gradient function ... I will appreciate if you are able to show me the workings to simplfying . Thanks.
Hello! Just a little update on my workings... Calculate the gradient of the tangent to the curve at and I can't simplify further. Am I on the right track?
Last edited by Punch; February 11th 2010 at 07:01 PM.
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