1.

We know that the slope of a line that is perpindicular to the other is equal to the negative recipricol of the known slope. That is to say; if the slope of a line is 1/2 then the slope of a line perpindicular to the first is -2. Or more formally;

m1.m2 = -1 ;where m1 and m2 are the respective slopes.

So for this question, you just use the slope equation;

m=(y2-y1)/(x2-x1)

and apply the above theory.

2.

You know the slope of the line they've given you the equation for is 2/3 by y=mx+b. So therefore you know the slope of the line you want is also 2/3 as it is parallel (has the same slope). Now you just need to find the equation, they've given you a point, so just use the line formula;

y-y1=m(x-x1)

where y1 and x1 are your x and y points that are given to you and 'y' and 'x' are left as variables, rearrange the equation.

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