Have you learnt the quotient rule?
Check it yourself here: differentiate 3t/(t^3-1) - Wolfram|Alpha
Click on Show steps.
Check this derivation please.
s= 3t/(t^3-1)
i have worked so far into this:
(3t)(t^3-1)^-1
(-3t)(t^3-1)^-2
(-3t)/(t^3-1)^2
I am not sure if I am doing this right.
Could some one check so far and finish it off for me.
The answer should be: -3(1+2t^3)/(t^3-1)^2.
I am not sure where the top (1+2t^3) comes from please check.
p.s = sorry about the quick posts i've done thanks for the help I have recieved. Thanks
Have you learnt the quotient rule?
Check it yourself here: differentiate 3t/(t^3-1) - Wolfram|Alpha
Click on Show steps.
You can do it this way, using the product rule rather than the quotient rule- but you didn't use the product rule.
(fg)'= f'g+ fg'
(-3t)(t^3-1)^-2
(-3t)/(t^3-1)^2
I am not sure if I am doing this right.
Could some one check so far and finish it off for me.
The answer should be: -3(1+2t^3)/(t^3-1)^2.
I am not sure where the top (1+2t^3) comes from please check.
p.s = sorry about the quick posts i've done thanks for the help I have recieved. Thanks