...I hope this is the right area to post this question.

Find the equation of the tangent to the curve y=2/x+1 at the point where x=3.

I had a go can somebody please check it thanks,

y=2/x+1 I assume you mean 2/(x + 1)

y=2/4

=1/2 (3,1/2)

2(x+1)^-1

-2(x+1)^-2

-2/(x+1)^2

2/(3+1)(3+1) Correct up to here. But remember that 4x4 = 16